The Scorpion and the Cricket
Inside a rectangular room measuring 30 feet in length and 12 feet in width and height, a scorpion is at a point on the middle of one of the end walls, 1 foot from the ceiling as shown in point A, and a cricket is on the center of the opposite wall, 1 foot from the floor, as shown at point B. What is the shortest distance that the scorpion must crawl to reach the cricket, which remains stationary? Of course, the scorpion never drops or falls, but crawls fairly.
Once I figured out that the scorpion was on the wall on the right of the box, 1 foot from the ceiling, and the cricket was on the wall on the left of the box, 1 foot from the floor, I figured I had it all figured out. I labeled the box with the dimensions that were listed in the initial problem, had the scorpion crawl down the right wall, across the floor, and up the left wall.
To me, clearly, the scorpion crawled 11 feet down the right wall, 30 feet across the bottom panel, and 1 ft up the left wall. 11ft+30ft+1 ft= 41 ft. So I figured the scorpion crawled 41 feet. When I got to class, the other students were discussing the phrase from the problem: "the shortest distance." When I really started to think about this problem, I realized that there MIGHT be a shorter distance that the scorpion could travel. I know that if the scorpion could fly, the shortest distance would be a straight, downward trending line through the air of the box, directly to the cricket (the shortest distance between two points is a straight line). That length of that line would be the absolute shortest way the scorpion could travel. But since the scorpion can not fly, it has to crawl. My instructor suggested that we explore nets to inspire an alternate path for the scorpion.
In the above image, you can see that the first net that a drew did not help me. Because I drew the cricket and the scorpion in such a way that they appeared in a straight line in relationship to each other, I could not figure out a way to draw the triangle I needed, so I abandoned this net. Net #2 allowed me to draw a diagonal line that the scorpion could travel, but because of where I positioned the side flaps on my diagram, it made the cricket and the scorpion even farther apart. In this diagram, I have one leg measuring 47 feet, and the other leg measuring 7 feet, making the hypotenuse measure 47.5 feet. This net created a diagonal line for the scorpion to travel, but the distance was longer than my initial distance. I saw that I needed to make my triangle's "legs" shorter in order to shorten the length of the hypotenuse. Net #3 solved the problem for me!
What a fun problem! The shortest distance the scorpion could travel is 40ft!